4.905x^2-24x+12=0

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Solution for 4.905x^2-24x+12=0 equation: 



4.905x^2-24x+12=0

a = 4.905; b = -24; c = +12;
Δ = b2-4ac
Δ = -242-4·4.905·12
Δ = 340.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-\sqrt{340.56}}{2*4.905}=\frac{24-\sqrt{340.56}}{9.81}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+\sqrt{340.56}}{2*4.905}=\frac{24+\sqrt{340.56}}{9.81}
$

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